# Solve the series: 13,19=>4 ...

**4**= 32.

71 + 9 = 80 | 8 x

**10**= 80

128 + 32 = 160 | 8 x

**20**= 160

Answer =

**20**.

Add 13+19=32, 71+9=80, 128+32=160. So now if the answers to following question is 4,10 then for the third one with respect with addition it can be 20. [ logical as 4*8=32, 10*8=80, 20*8=160].

So 128,32=>20.

Hope its right?

20.

13+19=32

71+9=80

128+32=160

all of the sums are multiples of 4 so divide them and see the logic.

The answer for this question will be 20.

The sum of the first two numbers is a multiple of 8.

By this logic you can easily calculate the answer as 20.

The answer for these question will be 20.

Add both numbers and check if that number is multiple of 8.

13+19=32. 8*4=32

71+9=80 8*10=80

128+32=160 8*20=160

So answer is 20.

There can be other interpretations. The data is too small.

Just to be cantankerous

13,19 => 4 (1**3**,**1**9 so 3+1=4)

71,9=>10 (7**1**,**9 ** so** **1+9=10)

128,32=>11 (12**8**,**3**2 so 8+3=11)

13+19=32 which is 4*8

71+9=80 which is 10*8

128+32=160 which is 20*8

All are multiples of 8 so the answer is 20