Solution to Grand Quiz Question #2
From figure we have,
[1] PR = QR
[2] QS = SR
-----------------------------------------------
In Figure 2, parallel to PQ, we draw SU
Because [1] and PQ || SU, we get
[3] RS =RU
[4] PS = QU
-----------------------------------------------
In Figure 3, we draw line PU.
From [4], and PQ = QP, and angle RPQ = RQP (=80),
the triangle PQS equals to triangle PQU.
So
[5] PU = QS
From [2], PU = SR
From [3], we get
[6] PU = RU
So angle RPU = 20, TPU = 10, UPQ = 60,
[7] SVU = 60
[8] PQ = QV = VP
From [5], [7] and [8], we get
[9] SU = UV = VS
-----------------------------------------------
In Figure 4, we draw UW vertical to PR.
From [6] and angle RPU = PRU, we get triangle PUW equals to triangle RUW. So
[10] PW = RW
-----------------------------------------------
Figure 5
In Figure 5, we draw RX.
From [10] and UW vertical to PR, we get
[11] angle SRX = SPX = 10
[12] RX = PX
From [11], we get
[13] angle URX = 10 = SRX
[13'] angle URX = UPX
[1] PR = QR
[2] QS = SR
-----------------------------------------------
In Figure 2, parallel to PQ, we draw SU
Because [1] and PQ || SU, we get
[3] RS =RU
[4] PS = QU
-----------------------------------------------
In Figure 3, we draw line PU.
From [4], and PQ = QP, and angle RPQ = RQP (=80),
the triangle PQS equals to triangle PQU.
So
[5] PU = QS
From [2], PU = SR
From [3], we get
[6] PU = RU
So angle RPU = 20, TPU = 10, UPQ = 60,
[7] SVU = 60
[8] PQ = QV = VP
From [5], [7] and [8], we get
[9] SU = UV = VS
-----------------------------------------------
In Figure 4, we draw UW vertical to PR.
From [6] and angle RPU = PRU, we get triangle PUW equals to triangle RUW. So
[10] PW = RW
-----------------------------------------------
Figure 5
In Figure 5, we draw RX.
From [10] and UW vertical to PR, we get
[11] angle SRX = SPX = 10
[12] RX = PX
From [11], we get
[13] angle URX = 10 = SRX
[13'] angle URX = UPX
Replies
-
Ankita Katdare
Figure 6
In Figure 6, extend RX to PQ.
From [13], and angle PQR = QPR = 80, we get
line RX vertical to PQ,
[14] line RX is the same as line RV
From [12], [13], [14], we get triangle RTX equals to triangle PVX. So
[15] TX = VX
From [12], [15], we get
[16] RV = PT
From [13'], [16], we get triangle RVU equals to triangle PTU. So
[17] TU = UV
--------------------------------------------------------
Finally
From [9], [17], we get
[18] TU = SU
Because SU || PQ, so
[19] angle RUS = RQP = 80
From [18], [19], we get
[20] angle STU = TSU = 50
So angle x = angle STU - angle PTU
= 50 - (180 - 70 - 60 - 20)
= 50 - 30
= 20
--------------------------------------------------------
This is just one of the solutions.
The fun about geometry is that, the same problem can have different approaches to land up to a solution.
We are expecting some logical approach (may be) different than what I mentioned above. 😀 -
Ankita KatdareYesterday's question's Coins will not be credited to anyone.
But the solution finding is still open to all.
Please come up with better solutions.
😀 -
ISHAN TOPRE
Thank You Madam. 😛AbraKaDabraYesterday's question's Coins will be credited to Issue. 😀
By the way here is the new solution.
If you are allowed to use a compass, actually drawing the figure will give you answer in 30 Sec. Do try it. Its fun.
All you need to do is to draw an Isosceles triangle with any suitable base length.
Remember that we have to play with angles. The length is immaterial. I did it. 😀 -
PraveenKumar PurushothamanWoah... Didn't expect it goes this much... Anyways, my solution was from Hand Drawing and CorelDraw. 😀
You are reading an archived discussion.
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