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# New math problem!

Assume that each statement is either true or false. What is the

unknown (whole) number from the following possibly

false statements:

-Crook-

unknown (whole) number from the following possibly

false statements:

- At least one of the last two statements in this list is true.
- This is either the first true or the first false statement in the list.
- There exist three consecutive false statements.
- The difference beween the numbers of the last true statement and the first true statement is a factor of the unknown number.
- The sum of the numbers of the true statements is the unknown number.
- This is not the last true statement.
- Each true statement's number is a factor of the unknown number.
- The unknown number equals the percentage of these statements which are true.
- The number of different factors which the unknown number has (excluding 1 and itself) is more than the sum of the numbers of the true statements.
- There are no three cosecutive true statements.

-Crook-

God forgive me for i cannot answer crooks question!! 😉😀😁😁

plz provide some clue..

I don't have a clue 😔

Try please

Crook

Try please

Crook

**ahh...**

goshhhhhhhh, i am happy enough that i could reach till the end of question!!! answer pleez.

plz give the answer crook

a long time has passed away..

a long time has passed away..

By 2, either way 1 must be false, and then so must both 9 and 10.

6, if false, says "This is the last true statement", which gives a paradox, thus

6 must be true, and so must 7 and/or 8.

7 and 8 cannot both be true, as the number had to be a multiple of 6,7,8 , that is a multiple of 168 (by 7), and less than 100 (by 8)

If 8 is false, then 3 is true (8,9,10 is false), if 8 is true, then 3 is false (3 cannot be true when both 6 and 8 are true, then there are no three consecutive statements left).

So we have either

A) F X F X X T F T F F or B) F X T X X T T F F F

In A), 4 and 5 must be true (by false 10), and 2 may be true or false. So by 5 the number shall be either 27 (2+3+4+5+6+7) or 25 (3+4+5+6+7). None of these can fulfill 8, though, so A) is out leaving us with B)

Now, (by 7) 3,6 and 7 are factors, the number must be a multiple of 42, as 2+3+4+5+6+7=27, 5 must be false.

By false 10, 2 and 4 must be true, that is 5 shall be a multiple of the number. Now the number must be a multiple of 2,3,4,5,6 and 7, that is a multiple of 3*4*5*7=420. 420 has 22 different factors

(2,3,4,5,6,7,10,12,14,15,20,21,28,30,35,42,60,70,84,105,140,210) and the sum 2+3+4+6+7 = 22, so the only multiple of 420 that fulfills false 9 is 420.

6, if false, says "This is the last true statement", which gives a paradox, thus

6 must be true, and so must 7 and/or 8.

7 and 8 cannot both be true, as the number had to be a multiple of 6,7,8 , that is a multiple of 168 (by 7), and less than 100 (by 8)

If 8 is false, then 3 is true (8,9,10 is false), if 8 is true, then 3 is false (3 cannot be true when both 6 and 8 are true, then there are no three consecutive statements left).

So we have either

A) F X F X X T F T F F or B) F X T X X T T F F F

In A), 4 and 5 must be true (by false 10), and 2 may be true or false. So by 5 the number shall be either 27 (2+3+4+5+6+7) or 25 (3+4+5+6+7). None of these can fulfill 8, though, so A) is out leaving us with B)

Now, (by 7) 3,6 and 7 are factors, the number must be a multiple of 42, as 2+3+4+5+6+7=27, 5 must be false.

By false 10, 2 and 4 must be true, that is 5 shall be a multiple of the number. Now the number must be a multiple of 2,3,4,5,6 and 7, that is a multiple of 3*4*5*7=420. 420 has 22 different factors

(2,3,4,5,6,7,10,12,14,15,20,21,28,30,35,42,60,70,84,105,140,210) and the sum 2+3+4+6+7 = 22, so the only multiple of 420 that fulfills false 9 is 420.

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come again?

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come again?

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do people in this thread have real lives?

You still doubt? 😉edie4someonedo people in this thread have real lives?

So is Jerry correct????Jerryblah... yak yak....blah blah blaah..

..

...blah

...

... ... ...etc

By false 10, 2 and 4 must be true, that is 5 shall be a multiple of the number. Now the number must be a multiple of 2,3,4,5,6 and 7, that is a multiple of 3*4*5*7=420. 420 has 22 different factors

(2,3,4,5,6,7,10,12,14,15,20,21,28,30,35,42,60,70,84,105,140,210) and the sum 2+3+4+6+7 = 22, so the only multiple of 420 that fulfills false 9 is 420.

What in the world is the answer

Only crook can tell!!

Is the answer 5040..😳, I think 1,8,9,10 were false...

This is a age old thread! But the question is very good!