New math problem!
Assume that each statement is either true or false. What is the
unknown (whole) number from the following possibly
false statements:
-Crook-
unknown (whole) number from the following possibly
false statements:
- At least one of the last two statements in this list is true.
- This is either the first true or the first false statement in the list.
- There exist three consecutive false statements.
- The difference beween the numbers of the last true statement and the first true statement is a factor of the unknown number.
- The sum of the numbers of the true statements is the unknown number.
- This is not the last true statement.
- Each true statement's number is a factor of the unknown number.
- The unknown number equals the percentage of these statements which are true.
- The number of different factors which the unknown number has (excluding 1 and itself) is more than the sum of the numbers of the true statements.
- There are no three cosecutive true statements.
-Crook-
Replies
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integratdbrainsGod forgive me for i cannot answer crooks question!! ๐๐๐๐
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aditiplz provide some clue..
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crookI don't have a clue ๐
Try please
Crook -
aashimaahh...
goshhhhhhhh, i am happy enough that i could reach till the end of question!!! answer pleez. -
aditiplz give the answer crook
a long time has passed away.. -
JerryBy 2, either way 1 must be false, and then so must both 9 and 10.
6, if false, says "This is the last true statement", which gives a paradox, thus
6 must be true, and so must 7 and/or 8.
7 and 8 cannot both be true, as the number had to be a multiple of 6,7,8 , that is a multiple of 168 (by 7), and less than 100 (by 8)
If 8 is false, then 3 is true (8,9,10 is false), if 8 is true, then 3 is false (3 cannot be true when both 6 and 8 are true, then there are no three consecutive statements left).
So we have either
A) F X F X X T F T F F or B) F X T X X T T F F F
In A), 4 and 5 must be true (by false 10), and 2 may be true or false. So by 5 the number shall be either 27 (2+3+4+5+6+7) or 25 (3+4+5+6+7). None of these can fulfill 8, though, so A) is out leaving us with B)
Now, (by 7) 3,6 and 7 are factors, the number must be a multiple of 42, as 2+3+4+5+6+7=27, 5 must be false.
By false 10, 2 and 4 must be true, that is 5 shall be a multiple of the number. Now the number must be a multiple of 2,3,4,5,6 and 7, that is a multiple of 3*4*5*7=420. 420 has 22 different factors
(2,3,4,5,6,7,10,12,14,15,20,21,28,30,35,42,60,70,84,105,140,210) and the sum 2+3+4+6+7 = 22, so the only multiple of 420 that fulfills false 9 is 420. -
xheavenlyx===============================================
come again?
=============================================== -
edie4someonedo people in this thread have real lives?
-
crook
You still doubt? ๐edie4someonedo people in this thread have real lives? -
xheavenlyx
So is Jerry correct????Jerryblah... yak yak....blah blah blaah..
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...blah
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... ... ...etc
By false 10, 2 and 4 must be true, that is 5 shall be a multiple of the number. Now the number must be a multiple of 2,3,4,5,6 and 7, that is a multiple of 3*4*5*7=420. 420 has 22 different factors
(2,3,4,5,6,7,10,12,14,15,20,21,28,30,35,42,60,70,84,105,140,210) and the sum 2+3+4+6+7 = 22, so the only multiple of 420 that fulfills false 9 is 420. -
deepesh142??
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Jeffrey ArulrajWhat in the world is the answer
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deepesh1Only crook can tell!!
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rahul69Is the answer 5040..๐ณ, I think 1,8,9,10 were false...
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Saandeep SreerambatlaThis is a age old thread! But the question is very good!
You are reading an archived discussion.
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