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crook
crook • Jun 20, 2006

New math problem!

Assume that each statement is either true or false. What is the
unknown (whole) number from the following possibly
false statements:

  1. At least one of the last two statements in this list is true.
  2. This is either the first true or the first false statement in the list.
  3. There exist three consecutive false statements.
  4. The difference beween the numbers of the last true statement and the first true statement is a factor of the unknown number.
  5. The sum of the numbers of the true statements is the unknown number.
  6. This is not the last true statement.
  7. Each true statement's number is a factor of the unknown number.
  8. The unknown number equals the percentage of these statements which are true.
  9. The number of different factors which the unknown number has (excluding 1 and itself) is more than the sum of the numbers of the true statements.
  10. There are no three cosecutive true statements.
What is the number? 😉

-Crook-
God forgive me for i cannot answer crooks question!! 😉😀😁😁
aditi
aditi • Aug 4, 2006
plz provide some clue..
crook
crook • Aug 5, 2006
I don't have a clue 😔

Try please

Crook
aashima
aashima • Aug 6, 2006
ahh...

goshhhhhhhh, i am happy enough that i could reach till the end of question!!! answer pleez.
aditi
aditi • Oct 25, 2006
plz give the answer crook
a long time has passed away..
Jerry
Jerry • Oct 25, 2006
By 2, either way 1 must be false, and then so must both 9 and 10.

6, if false, says "This is the last true statement", which gives a paradox, thus
6 must be true, and so must 7 and/or 8.

7 and 8 cannot both be true, as the number had to be a multiple of 6,7,8 , that is a multiple of 168 (by 7), and less than 100 (by 8)

If 8 is false, then 3 is true (8,9,10 is false), if 8 is true, then 3 is false (3 cannot be true when both 6 and 8 are true, then there are no three consecutive statements left).

So we have either
A) F X F X X T F T F F or B) F X T X X T T F F F

In A), 4 and 5 must be true (by false 10), and 2 may be true or false. So by 5 the number shall be either 27 (2+3+4+5+6+7) or 25 (3+4+5+6+7). None of these can fulfill 8, though, so A) is out leaving us with B)

Now, (by 7) 3,6 and 7 are factors, the number must be a multiple of 42, as 2+3+4+5+6+7=27, 5 must be false.

By false 10, 2 and 4 must be true, that is 5 shall be a multiple of the number. Now the number must be a multiple of 2,3,4,5,6 and 7, that is a multiple of 3*4*5*7=420. 420 has 22 different factors

(2,3,4,5,6,7,10,12,14,15,20,21,28,30,35,42,60,70,84,105,140,210) and the sum 2+3+4+6+7 = 22, so the only multiple of 420 that fulfills false 9 is 420.
xheavenlyx
xheavenlyx • Oct 28, 2006
===============================================


come again?




===============================================
edie4someone
edie4someone • Jul 17, 2007
do people in this thread have real lives?
crook
crook • Jul 17, 2007
edie4someone
do people in this thread have real lives?
You still doubt? 😉
xheavenlyx
xheavenlyx • Jul 21, 2007
Jerry
blah... yak yak....blah blah blaah..

..
...blah

...

... ... ...etc


By false 10, 2 and 4 must be true, that is 5 shall be a multiple of the number. Now the number must be a multiple of 2,3,4,5,6 and 7, that is a multiple of 3*4*5*7=420. 420 has 22 different factors

(2,3,4,5,6,7,10,12,14,15,20,21,28,30,35,42,60,70,84,105,140,210) and the sum 2+3+4+6+7 = 22, so the only multiple of 420 that fulfills false 9 is 420.
So is Jerry correct????
deepesh1
deepesh1 • Sep 26, 2012
42??
Jeffrey Arulraj
Jeffrey Arulraj • Sep 26, 2012
What in the world is the answer
deepesh1
deepesh1 • Sep 26, 2012
Only crook can tell!!
rahul69
rahul69 • Sep 29, 2012
Is the answer 5040..😳, I think 1,8,9,10 were false...
This is a age old thread! But the question is very good!

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