Leaf of Descartes
Someone,I need help in this.I have the answer but I can't think of a solution.I have tried a few things,though...
Parameterization of the leaf of Descartes.
y=tx => x= (3at)/(1+t^3)
y= (3at^2)/(1+t^3) (-infinity
And here are some things I have figured out,
When t<-1,
t+1<0, 1+t^3<0 and hence x>0
When 0>t>-1,
t+1>0, 1+t^3>0 and hence x<0
*Here are the hints my teacher gave me:
limx(t-->-1)= +/- infinity
limx(t-->-1,t<-1)=infinity
limx(t-->-1,t>-1)= -infinity
and here is the answer:
Parameterization of the leaf of Descartes.
y=tx => x= (3at)/(1+t^3)
y= (3at^2)/(1+t^3) (-infinity
And here are some things I have figured out,
When t<-1,
t+1<0, 1+t^3<0 and hence x>0
When 0>t>-1,
t+1>0, 1+t^3>0 and hence x<0
*Here are the hints my teacher gave me:
limx(t-->-1)= +/- infinity
limx(t-->-1,t<-1)=infinity
limx(t-->-1,t>-1)= -infinity
and here is the answer:
Replies
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PraveenKumar PurushothamanAnswer?
-
Aruwin
Yes,the graph and the table are the answer but i dunno the solution.Praveen-KumarAnswer? -
simplycoderRefer this, you would get the correct way atleast.
Folium Of Descartes -
Aruwin
Sorry,I have read through it and I have got the idea.But how come the graph that my teacher drew is different than that that is shown on wikipedia?simplycoderRefer this, you would get the correct way atleast.
Folium Of Descartes -
AruwinI am stucked now.
I have tried to differentiate dy/dx=(dy/dx)/(dx/dt) and I got [2t(1+t^3) - 3t^4]/(1-2t^3) but I am not sure if this is right or not.
So after I have differentiate this,what do I do next to make the graph table? -
AruwinHey guys,it is alright.I have solved it myself ๐ I searched on the internet about descartes folium and studied it and then i got it ๐
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PraveenKumar Purushothaman
Thats great... ๐AruwinHey guys,it is alright.I have solved it myself ๐ I searched on the internet about descartes folium and studied it and then i got it ๐ -
Dancer_EngineerGreat! ๐
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