**Leaf of Descartes**

Someone,I need help in this.I have the answer but I can't think of a solution.I have tried a few things,though...

Parameterization of the leaf of Descartes.

y=tx => x= (3at)/(1+t^3)

y= (3at^2)/(1+t^3) (-infinity<t<infinity)

And here are some things I have figured out,

When t<-1,

t+1<0, 1+t^3<0 and hence x>0

When 0>t>-1,

t+1>0, 1+t^3>0 and hence x<0

*Here are the hints my teacher gave me:

limx(t-->-1)= +/- infinity

limx(t-->-1,t<-1)=infinity

limx(t-->-1,t>-1)= -infinity

and here is the answer:

Parameterization of the leaf of Descartes.

y=tx => x= (3at)/(1+t^3)

y= (3at^2)/(1+t^3) (-infinity<t<infinity)

And here are some things I have figured out,

When t<-1,

t+1<0, 1+t^3<0 and hence x>0

When 0>t>-1,

t+1>0, 1+t^3>0 and hence x<0

*Here are the hints my teacher gave me:

limx(t-->-1)= +/- infinity

limx(t-->-1,t<-1)=infinity

limx(t-->-1,t>-1)= -infinity

and here is the answer:

Praveen Kumar Purushothaman

Branch Unspecified

7 years ago

Answer?

simplycoder

Branch Unspecified

7 years ago

Refer this, you would get the correct way atleast.

https://en.wikipedia.org/wiki/Folium_of_Descartes

https://en.wikipedia.org/wiki/Folium_of_Descartes

Sorry,I have read through it and I have got the idea.But how come the graph that my teacher drew is different than that that is shown on wikipedia?simplycoderRefer this, you would get the correct way atleast.

https://en.wikipedia.org/wiki/Folium_of_Descartes

Praveen Kumar Purushothaman

Branch Unspecified

7 years ago

Thats great... 😀AruwinHey guys,it is alright.I have solved it myself 😀 I searched on the internet about descartes folium and studied it and then i got it 😀

Dancer_Engineer

Branch Unspecified

7 years ago

Great! 😀

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