ish_nalini

Branch Unspecified

22 Dec 2006

**just solve it!!!**

Puzzle 1:

puzzle 2:

**Who stole the clock?****If Robort was the thief, he was telling the truth, Tommy did not steal but was telling a lie: Scott is innnocent. It meant Scott was the thief which was not true becasue we assumed Robert was the thief.**

If Scott was the thief, then both Robert and Tommy told a lie. It meant Tommy and Scott both were thief which was not true.

Tommy was the thief, what he said was true: Scott was innocent. Robert told a lie, which meant Tommy was the thief.If Scott was the thief, then both Robert and Tommy told a lie. It meant Tommy and Scott both were thief which was not true.

Tommy was the thief, what he said was true: Scott was innocent. Robert told a lie, which meant Tommy was the thief.

puzzle 2:

**Among 6 coins one is heavier than all the others. You can weigh only 2 times to find out which one is heavier.**reachrkata

Branch Unspecified

23 Dec 2006

Puzzle 2 solution :

Take 4 coins randomly and put two on either side of the balance

Case 1: Both sides are equal.

then the heavy coin is in the remaining 2 coins not chosen. The exact one can be found by one more weighing.

Case 2: One of the sides is heavier.

The heavier one is on that particular side. The exact one can be found by one more weighing.

😁

Yahoo !!!

Take 4 coins randomly and put two on either side of the balance

Case 1: Both sides are equal.

then the heavy coin is in the remaining 2 coins not chosen. The exact one can be found by one more weighing.

Case 2: One of the sides is heavier.

The heavier one is on that particular side. The exact one can be found by one more weighing.

😁

Yahoo !!!

ish_nalini

Branch Unspecified

23 Dec 2006

reachrkataPuzzle 2 solution :

Take 4 coins randomly and put two on either side of the balance

Case 1: Both sides are equal.

then the heavy coin is in the remaining 2 coins not chosen. The exact one can be found by one more weighing.

Case 2: One of the sides is heavier.

The heavier one is on that particular side. The exact one can be found by one more weighing.

😁

Great your right!!!!!!!!!!!!!!!!!!

pradeep_agrawal

Branch Unspecified

22 Feb 2008

Another approach that helps in optimizing other similar cases:

Step 1: Take 3-3 coins randomly and put on either side of the balance. This will give you a set of 3 coin which contain heavier coin.

Step 2: From the above obtained 3 coin set, take 1-1 coin randomly and put on either side of the balance and keep 1 coin separate.

Step 3: If the balance is unbalanced, the heavier coin is on the heavier side of balance, otherwise the third coin is the heavier coin.

Step 1: Take 3-3 coins randomly and put on either side of the balance. This will give you a set of 3 coin which contain heavier coin.

Step 2: From the above obtained 3 coin set, take 1-1 coin randomly and put on either side of the balance and keep 1 coin separate.

Step 3: If the balance is unbalanced, the heavier coin is on the heavier side of balance, otherwise the third coin is the heavier coin.

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