Java: double to int automatic conversion
int i = 1; i = i + 1.2;would result in compile time error. I understand that i + 1.2 would result in a float which can't be assigned to integer.
This code is error free and the result is an integer.
int i = 1; i += 1.2;This automatic narrowing is mind boggling.
Edit:
Had been searching for answer the whole day and someone finally answered it.
A compound assignment expression of the form E1 op= E2 is equivalent to E1 = (T)((E1) op (E2)), where T is the type of E1, except that E1 is evaluated only once.
from: #-Link-Snipped-#
Replies
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PraveenKumar PurushothamanIt is possible with an increment operator but instead you can do one thing. Type casting it to UpCast or DownCast, makes the program 100% error free!
Eg:int i = 1; i = (int)(i + 1.2);
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