Grand Quiz Question #2

Replies

• 

  Anoop Mathew

  x is 20 degrees. Exterior Angle is equal to interior opposite angle. angle ART is 20, so x also becomes 20
• 

  Anoop Mathew

  I meant angle SRT is 20, not ART...Typing mistake.
• 

  PraveenKumar Purushothaman

  The answer is 20 degrees. I drew it using hand and measured it. I can also be done as this way.
  R = 100 = 80 + 80 + R.
  P = 10.
  Mid Pt = 180 - 60 - 70 = 130.
  So, 150 - 130 = 20!
• 

  Kaustubh Katdare

  Do NOT make assumptions, folks 😀
• 

  Sagar07

  In triangle PQR, angle R=180-angle P- angle Q= 180- 80-80= 20....
  angle RTS is 90..
  hence in triangle RTS, angle RST=180- angle R- angle RTS=189-20-90=70
  angle PSQ=180-10-90=80
  
  hence angle TSQ=180- angle PSQ- angle RST=180-70-80=30
  
  in triangle TSO, x= 180-90-angle TSQ= 180-90-30=60
  
  assuming intersection point is o......
• 

  Sahithi Pallavi

  i can give you the explanation in this figure,
  so by considering the middle triangle,
  20+ (50-x)+ (150-x) = 180.
  220-2x = 180.
  40 =2x.
  x=20!
• 

  Sahithi Pallavi

  sorry, forgot to add this image
• 

  bhavna gupta

  Let the point inside the triangle be taken as A
  In triangle PQR
  According to the property 1:all the sum of all the angles of a triangle is 180 or 360
  therefore, P+Q+R=180
  80+80+R=180
  R=20
  
  In triangle RSQ
  as above property.......R+Q+S=180
  20+20+S=180
  S=140
  
  Now,acc to the property 2:sum of all the angles made across the line is 180
  therefore,In triangle POS...
  S=180-140
  S=40
  
  Again In triangle POS..
  P+S+O=180
  10+40+O=180
  O=130
  now In triangle POQ
  P+Q+O=180
  70+60+O=180
  O=50
  
  In triangle RST
  R+S+T=180
  20+140+T=180
  T=20
  
  now acc to property 2:
  O in triangle SOT
  130+O=180
  O=50
  
  acc to property 2:
  O in triangle QOT
  O=130
  
  In triangle QOT
  t=30
  now acc to property 2: At T
  T of triangle RST+T of triangle SOT+T of triangle QOT=180
  20+T+30=180
  Therefore Final answer is....T=130.......
• 

  Sudha Warad

  By Z property angle T=70, Given PTQ angle =90, and RTQ=180 so x=180-70-90=20.......
  thats all.........
• 

  Kaustubh Katdare

  Repeat: DO NOT make assumptions, please! :😀
• 

  CIVILPRINCESS

  X is 60
  
  the triangles RST AND QST are similar... since QS=SR (OPPOSITE ANGLES ARE 20) and they have a common side ST. (SSA congruency)
  
  i.e. RTS = STQ. => 90
  
  X+30 = 90. => X=60.
• 

  CIVILPRINCESS

  
  
  THE SIDEs I'VE marked (SQ and SR) are equal and one common side ST and one equal angle 20. so SAS congruency...
• 

  ultimate_k

  x is equal to 50 degree (trial and error method).
• 

  Guneet Khanuja

  x= 70 degree.
  method: let angle TSQ= y, and angle RST= z.
  therefore,
  y+z=140
  x+y=130
  z-x=10.
  and SR= SQ
• 

  eternalthinker

  Can't find a logical way to x!
  
  Appreciate the question anyways 😀
• 

  eternalthinker

  The thumbnail was from previous attempts to answer. Auto-saved!
• 

  lovejeet

  x=30...
  psq=180-spq-sqp=40------------A
  angle sot(o is the intersection of sq and tp)=50---------------B
  prq=20-----------------------C
  in triangle pts, pst=140-------------D
  THerefore, tsq=100...
  Therefore, x=180-100-50=30
  HENCE, X=30.
• 

  abhinaykumar

  by simple triangle method all angles in triangle= 180 using this equation we can solve the problem
  as we all can see there are two rightangled triangles
  using those we can say the angle of x is 20
• 

  sunil pal

  triangle STR&STQ
  ST=ST
  angle SQT=angle SRT
  in triangle SQR SR=SQ
  so angle RST=angle TSQ
  angle RSQ=140=angle RST+angle TSQ
  so angle RST = angle TSQ=70
  in triangle SPQ
  angle PSQ=40
  and angle PTQ=30
  and
  X+angle PTQ=90
  so
  X=60 ANS
  X=
• 

  Ankita Katdare

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