Find the number puzzle.

Replies

• 

  kedarjk

  2519
  I wrote a simple python program to find it out. 😉
• 

  Ankita Katdare

  kedarjk

  2519
  I wrote a simple python program to find it out. 😉

  Please share the script, friend! 😁
• 

  kedarjk

  Its no brainer...
  -----------------------------------------
  for i in range (1,3000):
  if i%9==8:
  if i%8==7:
  if i%7==6:
  if i%6==5:
  if i%5==4:
  if i%4==3:
  if i%3==2:
  if i%2==1:
  print "This is the number: "+ str(i)
  
  -----------------------------------------
  
  I was curious to check if there is really such number, so wrote a simple script. There must be some other logic to find it out.
• 

  Anoop Kumar

  That's an bad programming, number of loops will be 2519.
  
  This is class 8th problem which is calculated by following method, It's like following
  
  LCM (reminders) *x - GCD(Numbers) until you find the solution. x is an Integer.
  
  I don't remember that exact method.
• 

  Alok mishra

  ianoop

  That's an bad programming, number of loops will be 2519.
  
  This is class 8th problem which is calculated by following method, It's like following
  
  LCM (reminders) *x - GCD(Numbers) until you find the solution. x is an Integer.
  
  I don't remember that exact method.

  its n*LCM(divisor)-(difference Between divisor and remainder) , n is any natural number .
• 

  Anoop Kumar

  Another example of this question is
  find x such that
  reminder is 2 when divided by 3,
  3 when divided by 4,
  1 when it's 5.
• 

  smorgasbord

  Ankita Katdare

  There is a number less than 3000 that when divided by 2 leaves a remainder of 1, when divided by 3 leaves a remainder of 2, when divided by 4 leaves a remainder of 3, When divided by 5 leaves a remainder of 4, when divided by 6 leaves a remainder of 5, and so on up to nine.
  
  What is that number?
  Please provide step by step solution to this problem.

  A number when
  divided by 2 leaves a remainder of 1 = divided by 2 leaves a remainder of 1
  divided by 3 leaves a remainder of 2 = divided by 3 leaves a remainder of 1
  divided by 4 leaves a remainder of 3 = divided by 4 leaves a remainder of 1
  divided by 5 leaves a remainder of 4 = divided by 5 leaves a remainder of 1
  .
  .
  .
  . = divided by 9 leaves a remainder of 1
  
  Which means we need LCM of 2,3,4,5 ( 60 ), 7 ( 420 ), 8 (420*2=840), 9 ( 840*3 ) = 2520 ... and something.
  
  if we need all the right hand side of the ='s to be set right we need to add one to 2520, but we need all the left hand side of the ='s written above to be true, so need to subtract one from it.
  2519.
• 

  smorgasbord

  Hell! i made an egregious error:
  A number when
  divided by 2 leaves a remainder of 1 = divided by 2 leaves a remainder of -1
  divided by 3 leaves a remainder of 2 = divided by 3 leaves a remainder of -1
  divided by 4 leaves a remainder of 3 = divided by 4 leaves a remainder of -1
  divided by 5 leaves a remainder of 4 = divided by 5 leaves a remainder of -1
  .
  .
  .
  . = divided by 9 leaves a remainder of -1
  
  Which means we need LCM of 2,3,4,5 ( 60 ), 7 ( 420 ), 8 (420*2=840), 9 ( 840*3 ) = 2520, & -1 = 2519
  sorry. 😛