Find the digit ?

Replies

• 

  yadavundertaker mohit

  hi..can you please explain what "3 pairs of sum is 11 each" means.....only this condition is missing else the solution will be something like this
  
  Let five digit no. = a b c d e
  
  e=3a
  
  c+3=b
  
  d=b+2
  
  if condition first become clear then I can solve this..Please write the complete question accurately...
• 

  yadavundertaker mohit

  hi rengraj...where are you ?..please explain the first condition?....
• 

  CIVILPRINCESS

  rengaraj

  3 pairs of sum is eleven each.

  Does that mean any three pairs of digits which sum up to eleven?
• 

  cooltwins

  assuming the number is abcde, the answer i got is 65292.
  and this is purely based on trial and error method,along with the 3 simultaneous equations which are
  e=3a
  c+3=b
  d=b+4
  
  as there exist 3 pairs of digits summing up to eleven, a &e are surely not one of them as a+e=a+3a=4a (which is surely not a multiple of 11;-))
  now c+d=c+4+b=2c+7
  assuming this is equal to 11 =>c=2
  so d=9
  and b=5
  now assuming d+e is also equal to 11 we get e=2 =>a=6
  and the three pairs which sum up to 11 are :
  (a,b)(c,d)(d,e)
  
  P.S.i know this is fully suspended on assumptions and is prone to error....;-)
  correct me if i am wrong😁
• 

  Saandeep Sreerambatla

  Your method and process is correct but the number is wrong.
  
  e = 3a
  
  6 = 3 * 2
  
  So the number might be 25296.
  
  😀
• 

  yadavundertaker mohit

  yes ES is right ....
• 

  cooltwins

  yes i made a mistake 😡
  
  i took a=3e instead of 3a=e in the final step
  thanks for pointing out.....:smile:
  
  so there we have the answer:25296
  
  hope atleast this is correct.😁
• 

  yadavundertaker mohit

  cooltwins

  as there exist 3 pairs of digits summing up to eleven, a &e are surely not one of them as a+e=a+3a=4a (which is surely not a multiple of 11;-))
  now c+d=c+4+b=2c+7
  assuming this is equal to 11 =>c=2
  so d=9
  and b=5
  now assuming d+e is also equal to 11 we get e=2 =>a=6
  and the three pairs which sum up to 11 are :
  (a,b)(c,d)(d,e)

  
  you think one step ahead of everyone ..great..
• 

  cooltwins

  yadavundertaker

  you think one step ahead of everyone ..great..

  thanks yadav:smile:
• 

  rengaraj

  Sir,
  My system didn't work properly for few days. So, I was not able to connect. Any how, thanks for the various responses.
  Thanks,
  R.Rengaraj