Facebook Code: Let's Break It!

hi friend's,
Share your ideas to break this code.....
.
96449377495233753801945779474201809802672807196561564042232494827035653.....................2848158363880996154287853818516831857742271005203228107912992860281674398804941876553389634278444892842936309224242931230226726322698092627006733506038179452043047059973719222568487389442170752
shocking na...!!
As we know all the small letters ascii's are in 2-digit and space's ascii no is 32.So if this question's are in ascii we must find 32 at some regular interval.
So i don't think these question's are in ascii...!!
.
anyone have idea to break this code....?

Replies

  • Kaustubh Katdare
    Kaustubh Katdare
    Isn't it a prank by Facebook? They say it on their wall.
  • Morningdot Hablu
    Morningdot Hablu
    What is Prank...?
  • Kaustubh Katdare
    Kaustubh Katdare
    Try this: Google
  • Morningdot Hablu
    Morningdot Hablu
    Oh shit due to my examination i am not able to submit my answer on the correct time.
    But here goes the answer of first question....
    .
    import java.io.*;
    class x
    {
        int meth(int x,int h7)
        {
            int p=0,g=0,k=0,n=0;
            int res[]=new int[100];
            int a[]=new int[30];
            int arr[]=new int[60];
            int arr1[]=new int[60];
            for(int i=1;i<=x;i++)
            {
                p=(int)Math.sqrt(i);
                if(p*p==i)
                {
                    a[k]=p;
                    k++;
                }
            }
            for(int j=0;j<=k;j++)
            {
                for(int m=0;m<=k;m++)
                {
                    if(((a[j]*a[j])+(a[m]*a[m]))==x)
                    {
                        if(a[j]==a[m])
                        n++;
                        n++;
                        arr[g]=(a[j]*10)+a[m];
                        arr1[g]=(a[m]*10)+a[j];
                        g++;
                    }
                }
            }
            for(int h=0;h=1 && c<=100)
                {
                    while(i!=c)
                    {
                        b[i]=isr.readLine();
                        i++;
                    }
                }
                else
                {
                    System.out.println("out of limit");
                }
            }
            catch(Exception e)
            {
            }
            x d=new x();
            for(int j=0;j<=i;j++)
            h1=d.meth(Integer.parseInt(b[j]),h1);
        }
    }
            
            
    
  • Kaustubh Katdare
    Kaustubh Katdare
    What exactly is that?
  • Manish Goyal
    Manish Goyal
    Damn these were the questions guys
    #-Link-Snipped-#

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