Facebook Code: Let's Break It!
hi friend's,
Share your ideas to break this code.....
.
As we know all the small letters ascii's are in 2-digit and space's ascii no is 32.So if this question's are in ascii we must find 32 at some regular interval.
So i don't think these question's are in ascii...!!
.
anyone have idea to break this code....?
Share your ideas to break this code.....
.
96449377495233753801945779474201809802672807196561564042232494827035653.....................2848158363880996154287853818516831857742271005203228107912992860281674398804941876553389634278444892842936309224242931230226726322698092627006733506038179452043047059973719222568487389442170752shocking na...!!
As we know all the small letters ascii's are in 2-digit and space's ascii no is 32.So if this question's are in ascii we must find 32 at some regular interval.
So i don't think these question's are in ascii...!!
.
anyone have idea to break this code....?
Replies
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Kaustubh KatdareIsn't it a prank by Facebook? They say it on their wall.
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Morningdot HabluWhat is Prank...?
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Kaustubh KatdareTry this: Google
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Morningdot HabluOh shit due to my examination i am not able to submit my answer on the correct time.
But here goes the answer of first question....
.
import java.io.*; class x { int meth(int x,int h7) { int p=0,g=0,k=0,n=0; int res[]=new int[100]; int a[]=new int[30]; int arr[]=new int[60]; int arr1[]=new int[60]; for(int i=1;i<=x;i++) { p=(int)Math.sqrt(i); if(p*p==i) { a[k]=p; k++; } } for(int j=0;j<=k;j++) { for(int m=0;m<=k;m++) { if(((a[j]*a[j])+(a[m]*a[m]))==x) { if(a[j]==a[m]) n++; n++; arr[g]=(a[j]*10)+a[m]; arr1[g]=(a[m]*10)+a[j]; g++; } } } for(int h=0;h
=1 && c<=100) { while(i!=c) { b[i]=isr.readLine(); i++; } } else { System.out.println("out of limit"); } } catch(Exception e) { } x d=new x(); for(int j=0;j<=i;j++) h1=d.meth(Integer.parseInt(b[j]),h1); } } -
Kaustubh KatdareWhat exactly is that?
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Manish GoyalDamn these were the questions guys
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