crack this puzzle if you can(all aeans)

Replies

• 

  shah pooja

  yar this is her personel matter,what v d enginners can do against a queen's dicision...............
  ha...ha.................
  
  
  
  it was just 4 jock as i was not getting d clue.well i tried to find out in d next post.
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  shah pooja

  may be she assumed the time when she was sending the messanger & by den she started counting on behalf of guess.
  or may be when he returned back & he might have told d time which was happening at d time he was at her aunt's home.so when he returned back den queen have asked his speed & calculated it by using t=d/v.
• 

  Kaustubh Katdare

  Pooja - it would be very nice if you could post only in English. Also, please avoid SMS text while posting on CE Forums.
• 

  nishank_eureka

  Well I think the queen had told to bring the clock of her aunt so that she can see the time and reset her clock.
  After reseting she will send her messenger again to her aunt's house to give back the watch and of course with a big thank you message 😎.
• 

  gohm

  above is the right answer!
  
  although why didn't see just call on the phone... lol.
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  nishank_eureka

  The messenger will start counting as soon as he will reach aunt's house at a constant speed. There he rested for sometime so he can calculate that how many numbers he have counted during his stay.As soon as he will leave he will see the time again and will continue counting till he reaches the castle.From his counting he can calculate how much time has elapsed from the time he had left the aunt's house. In this way queen can reset the watch to the exact time.
  
  This is the only possible solution which i can think of. Waiting for the answer.
  Hope the answer matches with my solution.
• 

  nishank_eureka

  The queen will start her watch as soon as the messenger leaves for aunt's house. Suppose the time taken by the messenger to reach the aunt's house is t hours.Since, he will come back at the same speed so the total time taken by the messenger for the return trip will be 2t + w .. where w is the waiting time in the aunt's house.The messenger will see the time in aunt's house before leaving.Suppose the time in her watch at that time is T hours. So, the time in queen's watch will be T+t when the messenger arrives in castle. Since queen knows t and messenger knows T and w , so she can easily reset her watch at the exact time.😁
  Thanks
  Nishank Rajvanshi
• 

  anand017

  nishank your answer, first one seems to be logical...
• 

  nishank_eureka

  Both are logical but second one is more mathematical.😎
• 

  Raviteja.g

  nishank, you did well :clap:
  the answer is
  Queen Georgia set her clock to 12:00 when the messenger left for her aunt`s house. When the messenger arrived at her aunt`s house, he noted the exact time and then rested. He left the aunt`s house exactly 2 hours later. He traveled at the same speed in both the directions. This way, when he arrived back, the total elapsed time was 2 hours plus twice the travel time (say t).
  
  So, when the messenger came back, Queen Georgia`s clock read (12:00 + 2:00 + 2t). So, she can immediately calculate the value of "t" by seeing the time of arrival of the messenger. The messenger had noted the exact time in the aunt`s clock (say "T") just before he left for the journey back. It took him "t" time to travel back. So, the correct time when the messenger came back was (T + t). So, Queen Georgia knew the correct time as both of these are known quantities.