Stiffness of Spring???

Replies

• 

  Voltaire

  Good question that tests your insight.
  The standard formula is F = kx where k is the proportionality constant (spring constant) and x denotes the amount of deformation from the original length.
  Look up Hooke's law of compression/stretching of a solid rod. You will notice that k corresponds to YA/L[sub]0[/sub] and that x corresponds to DL
  What do you think is the answer to your question and what is your reasoning?
• 

  samarjeetsaigal

  thanks for explaining the formula... i don't know this answer, i only got the question not the answer???
  anyway thanks for the reply
• 

  Voltaire

  You have to try first
  Sorry
• 

  vvishwaskumar

  samarjeetsaigal

  thanks for explaining the formula... i don't know this answer, i only got the question not the answer???
  anyway thanks for the reply

  stiffness will be 20 N/m...its right na...?
• 

  Voltaire

  How did you calculate that answer and what is your reasoning?
• 

  vvishwaskumar

  Voltaire

  How did you calculate that answer and what is your reasoning?

  hello..
  f=kx..if f is constant and x (length) is half then k will be double..if m wrong then make me right..sorry..!!
• 

  Voltaire

  No need to be sorry 😀
  
  You are right
  
  Hooke's law defines the spring constant as a characteristic of a spring which is defined as the ratio of the force affecting the spring to the displacement caused by it.
• 

  070790vivek

  vvishwaskumar

  hello..
  f=kx..if f is constant and x (length) is half then k will be double..if m wrong then make me right..sorry..!!

  here X does not define the length of spring it defines the deformation of spring on applying load
  in my view there should be other ans😕
• 

  Voltaire

  I have to admit that I, too, struggled with this one because L[sub]2[/sub]/L[sub]1[/sub] is a ratio end I would have thought that the ratio would be the same for both coils. Apparently it is not! The shorter spring does not conform to the same ratio as the longer spring if the same force is applied. One has to think of it as a rubber band: a one metre band will stretch to say 2 metres while a [sup]1[/sup]/[sub]2[/sub] metre band of the same material will stretch to only say [sup]3[/sup]/[sub]4[/sub] metres if the same force is applied.
• 

  Capt Spark

  This is the helical spring stiffness formula:
  
  
  If you cut into half, n is halved.. so k gets doubled
  It can be correlated to the stiffness of a uniform bar in tension too (K=AE/L). L reduces, K increases.
  Lots of things are easily available on this question in Google
• 

  070790vivek

  Ya very good this is the correct explanation & answer of this question.
  
  I m totaly agree with u.
  In study of design of springs( m.d.) we have to use this equation
• 

  Krishna Moorthy

  thanks for the answerwhich makes me to free from confusion
• 

  Krishna Moorthy

  Thanks for the information