a stone is dropped from a captive balloon at an elevation of 1000ft,. two sec later another stone is projected vertically upward from the ground with a velocity of 248ft per sec. if g is 32ft per sec squared when and where will the stones pass each other?
Doesn't look like a difficult question to me. Have you attempted it on your own? Share the steps you'd write to solve this so that we can help you find the correct answer
d1 = 0 + 1/2*32*t1^2 (1000-d1) = 248 * (t1-2) - 1/2 * 32 *(t1-2)^2 Solve the equations... t1 = 5 After 5 seconds, so 400 from top and 600 mt from ground. -CrazyGirl
