Effect of one control specification on another in printf statement.
CASE A :
-1202590843,-38367267551084304000000000000000000000000000.000000,0.000000
Output in B:
8,8.987654,0.000000
how is the value to be printed differing in both cases that is when i give wrng value fr %d conversion specification in CASE A ,then it also prints wrong value of its immediate format string ,so here %f tries to print some wiered value each time while the other % lf coreesponds to print the value 0.000000 so hw is it that this %d format string affecting the values to be printed corresponding to other format strings ,becoz when in CASE B ,on giving correct value for %d remove,i m getting crect answers .
#includeCASE B:#include int main() { int y = (8,9); printf("%d ,%f , %lf", 8.76, 8.987654); getch(); return 0; }
#includeOutput in A:#include int main() { int y = (8,9); printf("%d, %f, %lf",8 , 8.987654); getch(); return 0; }
-1202590843,-38367267551084304000000000000000000000000000.000000,0.000000
Output in B:
8,8.987654,0.000000
how is the value to be printed differing in both cases that is when i give wrng value fr %d conversion specification in CASE A ,then it also prints wrong value of its immediate format string ,so here %f tries to print some wiered value each time while the other % lf coreesponds to print the value 0.000000 so hw is it that this %d format string affecting the values to be printed corresponding to other format strings ,becoz when in CASE B ,on giving correct value for %d remove,i m getting crect answers .
Replies
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Koushal PatelStatement is correct, but to make this conversion you must cast variable you wish to convert, not just assign it to another int variable.
This causes problems also in the printf statement, since you are printing a float variable with int specifier %d without a cast.
Fix you're code like this:
printf("%d\n", (int) x);
^
| this is the cast operation
and it will correctly print integer value for 8.76
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