I had read this generalised rule somewhere. But I am not sure. If I have 7.9 CGPA, multiply it by 9.5= 75.05% If I have 80%, CGPA= 80/9.5=8.42

CGPA is defined on all student's comparative performance. suppose in 100 mark paper highest mark secured by topper is 90 marks then. 90 marks will be 100% and if student x will get 80 marks then CGPA of student x will be: 100/90*80 = 88.89 . on scale of 10 its 8.9.

I found it on one of the CBSE sites,which validates both the points mentioned above: ----- Full Form of CGPA ? Cumulative Grade Point Average. What is CGPA ? It is an overall indicative percentage of marks. How to calculate percentage from CGPA ? Multiply the CGPA with 9.5 or use the above calculator to get the indicative percentage. Why multiply with 9.5 only ? The Board took the result of the last five years and calculated the average marks of all candidates who had scored between 91 and 100. That average turned out to be close to 95 marks. Since the equivalent Grade Point for the 91-100 band (A1 grade) of marks is 10, it then divided the average result of 95 by 10. The result is 9.5. -----

So, isn't there a standard rule for doing that? What formula does calculator apply? Or will it vary from institution to institution? Knowing this can help a lot to calculate it ourselves while applying to certain universities that specifically ask for CGPA instead of percentages.

To my Knowledge,it differs from univ to univ.Earlier when i needed i found one in internet and applied but later i got a formula from our Univ where the result differed.so its better to ask your Univ COE section for clear and clarifications if needed.

There is a program of standard deviation (statistics). It takes the marks of topper as reference 10 pointer. and the lower extreme is 45-50% in VNIT( Which this means 0 pointer). Depending on the lower and higher maximum, windows of 1, 2, 3...10 pointer is decided. The window is usually. of 4-5 marks If topper gets below lower extremum everyone fails. (This of course never happens but only a worst case possibility.)

Thanks for sharing that information. I am sure it will be useful for many students. I wish we could collect the data for this conversion in one place.