c program to check no. is even or odd without using conditional operator !!

Replies

• 

  Anoop Kumar

  Good program but in wrong category.
  You should post computer and IT related stuffs at following section:
  #-Link-Snipped-#
• 

  nareshkumar6539

  Gaurav v. Deshmukh

  #include
  #include
  
  int main()
  {
    int no;
    char ch[0]="Even";
    char ch[1]="odd";
    printf("Enter a no. \t");
    scanf("%d",&no);
  
    printf("\n The no. is %s",ch[no%2]);
  
  return (0);
  }
  

  // in above c code using % operator and array we can find the no. is even or odd also we can perform it by using bitwise AND operato (&) and AND operator (&&).................
  I gave u the hint can anybody is able to write 2nd program ...😉😀//
  
  o/p--> Enter a no. 7
  The no. is odd
  
  Enter a no. 4
  The no. is Even

  When we use logical and or bit wise first it will convert number into binary format then it will perform the operation.
  When we perform Logical and or Bitwise and operation with NUMBER&&1 it will give
  one means it is ODD number it will give 0 means EVEN number.
  (NUMBER&&1)?"ODD":"EVEN" or (NUMBER&1)?"ODD":"EVEN"
• 

  rahul69

  nareshkumar6539

  When we use logical and or bit wise first it will convert number into binary format then it will perform the operation.
  When we perform Logical and or Bitwise and operation with NUMBER&&1 it will give
  one means it is ODD number it will give 0 means EVEN number.
  (NUMBER&&1)?"ODD":"EVEN" or (NUMBER&1)?"ODD":"EVEN"

  Logical And will not work! because logical And can only check if the number is non zero, to check even odd, you will have to use bitwise And ie '&'
• 

  Vinut47

  7 easy ways to find whether a number id odd/even.
  #-Link-Snipped-#