Approach involved while solving below questions
First question.. ,ques no,in this question actually i am not able to understand the approach involved..
Second question.. ques 20 ,In this ques according to me answer should be 2 but answer is 3.,so plz help
Second question.. ques 20 ,In this ques according to me answer should be 2 but answer is 3.,so plz help
Replies
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Kaustubh KatdareI'm tempted to tag #-Link-Snipped-# who cracked all such questions and went to IIM Indore. I always got severe headaches upon reading those questions. -
Prasad AjinkyaI'd say that the solution sheet is wrong 😀
Regarding the first question (money order), its a simple equation. commission = (floor((x - 0.01)/10) + 1 )/2 ... use this formula on both the amounts (71 and 47). You will get the answer (correctly marked)
Regarding the second question, for 11 coins, lets say in the first round X picks x1 and Y picks y1. so for X to win, we know that
11 - x - y <= 6 (since X is smart and wants to finish the game in the second round)
11 - x - y > 1 (at the end of one round, at least 1 coin is remaining)
and x <= 5, x >= 1
and y <= 5, y >= 1
I'd guess x to be 4 (since that way, whatever Y picks, X can pick just the right amount to keep just 1 coin in the 2nd round). Which brings me to why I think the soln sheet is wrong. -
Kaustubh Katdare☕ ...I'll envy you for my life, #-Link-Snipped-# .
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Ramani AswathThe coin problem has multiple solutions: 2, 3 and 4 are all valid. In my opinion the question is wrongly worded. If it were: "How many should he not pick up in the beginning to ensure a win no matter what strategy Y adopts?" the answer would be 5.
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public class qu11 {
int fun(int num)
{int count=0;
while(num>0)
{
count++;
num<<=1;
}
return count;
}
public static void main(String aa[])
{
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