C ++ Programing Challenge: Complete the code

[The_Big_K]

Puzzle Source: Cprogramming.com: C++ Programming Challenge - Guessing Game Challenge

The following program will act as a guessing game in which the user has eight tries to guess a randomly generated number. The program will tell the user each time whether he guessed high or low:

#include <stdlib.h>
#include <iostream>
  using namespace std;  int main()
{
int number=rand()___; 
int
guess=-1;
int trycount=0;
while(guess__number __ trycount<8)
{

cout__"Please enter a guess: ";
cin__guess;
__(guess_number)

cout<<"Too low"<<endl;
 __(guess_number)

cout<<"Too high"<<endl;
_______________;
_

if(guess==number)
cout<<"You guessed the number";
____

cout<<"Sorry, the number was: "<<_____;
______
0;

Those who want to scratch your brain and improve your C++ programming skills - discuss the problems.

Those who need spoon feeding, get the solution at the puzzle source.

[The_Big_K]

I sit and wonder why we don't have a code cracker in our 18,000+ engineers' squad.

[bayazidahmed]

Originally Posted by The_Big_K

I sit and wonder why we don't have a code cracker in our 18,000+ engineers' squad.

Naah! Again too easy.

[The_Big_K]

Ok, bayazidahmed - how about posting the solution and proving your point?

[bayazidahmed]

Originally Posted by The_Big_K

Ok, bayazidahmed - how about posting the solution and proving your point?

Well, If you insist.

#include <stdlib.h>
#include <iostream>
using namespace std; int main()
{
int number=rand() * 1; /*this blank could be used to scale the number, if we give it as * 1, the max number could be upto STD_MAX defined in stdlib.h which is usually 32767*/
int
guess=-1;
int trycount=0;
while(guess != number && trycount<8)
{

cout<<"Please enter a guess: ";
cin>>guess;
if(guess<number)

cout<<"Too low"<<endl;
if(guess>number) // here else if can also come in place of if

cout<<"Too high"<<endl;
trycount++;
}

if(guess==number)
cout<<"You guessed the number";
else

cout<<"Sorry, the number was: "<<number;
return
0;
}//you missed this bracket

[friendster7]

Originally Posted by bayazidahmed

Well, If you insist.

#include <stdlib.h>
#include <iostream>
using namespace std; int main()
{
int number=rand() * 1; /*this blank could be used to scale the number, if we give it as * 1, the max number could be upto STD_MAX defined in stdlib.h which is usually 32767*/
int //error in this line it must be int guess=-1;
guess=-1;
int trycount=0;
while(guess != number && trycount<8)
{

cout<<"Please enter a guess: ";
cin>>guess;
if(guess<number)

cout<<"Too low"<<endl;
if(guess>number) // here else if can also come in place of if

cout<<"Too high"<<endl;
trycount++;
}

if(guess==number)
cout<<"You guessed the number";
else

cout<<"Sorry, the number was: "<<number;
return
0;
}//you missed this bracket

ur code would not give a result.

[bayazidahmed]

Originally Posted by friendster7

ur code would not give a result.

Too bad, you should have tried compiling and posted your comments. It works perfectly fine for me.

The syntax error you have pointed out will not come in any compiler.

For your information, a single C/C++ statement can be spanned on multiple lines. The statement ends with a ; only.
So, there is nothing wrong in writing
int guess = -1 as
int
guess=-1
OR
int



guess=-1
OR
int
guess
=-1
OR
int
guess
=
-1

[niraj.kumar]

calm down ahmed

[bayazidahmed]

Originally Posted by niraj.kumar

calm down ahmed

Me? No worries. I was just explaining...