CrazyEngineers Forum

******************************************
Welcome To CrazyEngineers (CE) – an online community of engineers from all over the world! With the younger CEan at 84 and the youngest at 16, CE boasts of professional engineers, students, professors, entrepreneurs, CEOs, geeks & nerds. We exchange innovative ideas, share knowledge, help each other and expand our worldwide network of engineers! You need not have a formal degree in engineering to be a part of CrazyEngineers! Need we say more?
Join CE! | Be a CE Ambassador! | Forgot password? | Sponsor CE | Contact Us
Navigation
Go Back   CrazyEngineers Forum > CE : Technical Discussions > Chemical & Metallurgy Engineering
Reply

  #1 (permalink)
Old 20th September 2007, 11:45 AM
Author, Consultant
 
I'm a Crazy Chemical Engineer
Join Date: 20th September 2007
Location: Newport Beach, California, USA
Posts: 16
Post Cooling tower material balances (Chemical Engineering)

Here are the governing relationships for the makeup flow rate, the evaporation and windage losses, the draw-off rate, and the concentration cycles in an evaporative cooling tower system:



M = Make-up water in m³/hr
C = Circulating water in m³/hr
D = Draw-off water in m³/hr
E = Evaporated water in m³/hr
W = Windage loss of water in m³/hr
X = Concentration in ppmw (of any completely soluble salts … usually chlorides)
Xm = Concentration of chlorides in make-up water (M), in ppmw
Xc = Concentration of chlorides in circulating water (C), in ppmw
Cycles = Cycles of concentration = Xc / Xm
ppmw = parts per million by weight

A water balance around the entire system is:

M = E + D + W

Since the evaporated water (E) has no salts, a chloride balance around the system is:

M (Xm) = D (Xc) + W (Xc) = Xc (D + W)

and, therefore:

Xc / Xm = Cycles = M / (D + W) = M / (M – E) = 1 + {E / (D + W)}

From a simplified heat balance around the cooling tower:

(E) = (C) (∆T) (cp)/ Hv

where:
Hv = latent heat of vaporization of water = ca. 2260 kJ / kg
∆T = water temperature difference from tower top to tower bottom, in °C
cp = specific heat of water = ca. 4.184 kJ / kg / °C

Windage losses (W), in the absence of manufacturer's data, may be assumed to be:

W = 0.3 to 1.0 percent of C for a natural draft cooling tower
W = 0.1 to 0.3 percent of C for an induced draft cooling tower
W = about 0.01 percent of C if the cooling tower has windage drift eliminators
Concentration cycles in petroleum refinery cooling towers usually range from 3 to 7. In some large power plants, the cooling tower concentration cycles may be much higher.

(Note: Draw-off and blowdown are synonymous. Windage and drift are also synonymous.)
__________________
Milt Beychok
(Visit me at www.air-dispersion.com)

Last edited by mbeychok : 20th September 2007 at 09:50 PM. Reason: Cahnged post icon
mbeychok is offline  
Digg this Post!Add Post to del.icio.usBookmark Post in TechnoratiFurl this Post!
Reply With Quote
Sponsored links
Reply


Thread Tools Search this Thread
Search this Thread:

Advanced Search
Display Modes

Posting Rules
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts

vB code is On
Smilies are On
[IMG] code is On
HTML code is Off
Trackbacks are On
Pingbacks are On
Refbacks are On



All times are GMT +5.5. The time now is 12:39 AM.
Powered by vBulletin® Version 3.6.7
Copyright ©2000 - 2008, Jelsoft Enterprises Ltd.
Search Engine Friendly URLs by vBSEO 3.1.0
Member comments are owned by the poster. Copyright © 2005-2008 CrazyEngineers.com. All rights reserved.Ad Management by RedTyger