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CE - Apprentice
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ANS: (2,2,9)
As per the first two conditions the probable ages are (1,1,36),(1,2,18),(1,3,12),(1,4,9),(1,6,6),(2,3,6) ,(3,3,4) and (2,2,9). Professor know her berth number but he don't get the answer. That is sum of the ages of the children can make in two or more ways.That reduces the chances to two { (2,2,9),(1,6,6) }. From the third option, we got a constraint that, there is only one elder child. And we got the answer of (2,2,9) |
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