Hi,
Tell me friends if my approach is correct or not?
- Lets the speed of last soldier as A is V1 and of first soldier as B is V2
- The only thing same in cases is Time.
- Lets the distance traveled by A to meet B is 10+X, means total distance traveled by A is 10+2X and by B is 10
- When A meet B:
- Time is same, so time = dist/speed
- (10+X)/V1 = X/V2
- (10+X)V2 = X .V1-----(i)
- When A return back to position:
- Again time is same :
- (10+2X)/V1 = 10/V2
- (10+2X)V2 = 10 .V1-----(ii)
- Dividing equation i/ii
- U will get X = sqrt of 50 ~ 7.07
- Distance Traveled by A = 10+2X = 24.1 m
~Archana