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  #21 (permalink)
Old 19th December 2007, 07:01 PM
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Default Re: Queue Problem

let me guess the answer , the correct answer is 10 meters as the initial position of first soldier is the final position of the last soldier
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  #22 (permalink)
Old 20th December 2007, 10:54 AM
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Default Re: Queue Problem

Hi,

Tell me friends if my approach is correct or not?
  • Lets the speed of last soldier as A is V1 and of first soldier as B is V2
  • The only thing same in cases is Time.
  • Lets the distance traveled by A to meet B is 10+X, means total distance traveled by A is 10+2X and by B is 10
    • When A meet B:
      • Time is same, so time = dist/speed
        • (10+X)/V1 = X/V2
        • (10+X)V2 = X .V1-----(i)
    • When A return back to position:
      • Again time is same :
        • (10+2X)/V1 = 10/V2
        • (10+2X)V2 = 10 .V1-----(ii)
  • Dividing equation i/ii
    • U will get X = sqrt of 50 ~ 7.07
    • Distance Traveled by A = 10+2X = 24.1 m
~Archana
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  #23 (permalink)
Old 20th December 2007, 02:34 PM
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Default Re: Queue Problem

Archana & LORD_EC got the solution!

Congratulations!
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