Can you guess the numbers?

[The_Big_K]

Originally Posted by ntr_youngtiger

134

What's that?

[anuragh27crony]

@The_Big_K ...plzz comment on my answer in the recent post.......
whether my solution is right or not

[The_Big_K]

Originally Posted by anuragh27crony

@The_Big_K ...plzz comment on my answer in the recent post.......
whether my solution is right or not

Okay, here's my comment -

If Ash knew the that the sum of numbers is 5. Then he'd have following options in his mind -

(1,4), (2,3)

But, he knew the numbers are both greater than one. Then, he'd not have said the following -

Ash: I can't determine what are these numbers.

That is, Ash could not determine the numbers for sure!

So, unfortunately, we need some hard thinking over here, I think.

[anuragh27crony]

big_k answer please.......can't wait...for long time

[The_Big_K]

Sorry sire, the answer will not come. Its open for the non-quitters . Come on, try harder!

[barryn56]

Interesting - I'm not sure the problem is correctly posed, since it is obvious given only the sum of the two numbers that you would not be able to derive a solution. Adding that a solution "should" be possible, the assumption would be that you only consider unique values, which for sums gives 4 values: 5, 6, 98 and 99.
Based on a=x+y and b=xy, then x=b/y and y2-ay+b=0, so y=(a+sqrt(a2-4b))/2. The list of integer values of this function for 1<x,y<51 has a number of pairs of results, which makes it diffcult to see how the additional data that there isn't a unique result, helps produce a unique result. Please check the question is accurate.

[The_Big_K]

barryn,

Are you completely ignoring the dialogue between Ash & MaRo? Its there - and it's got all the clues you need to crack the problem.

CEan - anuragh27crony was making a good progress, but looks like he's given up

Think harder.

[anuragh27crony]

@Big_k....
Ash: I can't determine what are these numbers.
MaRo: Ah, i knew you wouldn't be able to do this.

i can't deduce the significance of these dialouges in solving problem....

Hint please....

[barryn56]

Are you sure you don't mean their PRODUCT is less than 100?? Otherwise I don't think this is solvable, because there are many solutions...

[The_Big_K]

The conditions have been mentioned and they haven't changed so far. Shall I post the answer or wait for few more days?