let x^(p/q)=y
take log on both sides
log x^(p/q)=log(y)
(p/q)*log(x)=logy
antilog((p/q)*log(x))=y
I think you want to create a program for this because such values can easily be calculated using scientific calculator
Am i right?
This is a discussion on How we find x^(p/q) within the CE - Quiz | Puzzles | Mathematics forums, part of the CE : General Discussions category; Any one know how we can find (P/Q)th power of x or how we can find x^ (p/q)...

Any one know how we can find (P/Q)th power of x or how we can find
x^ (p/q)![]()






let x^(p/q)=y
take log on both sides
log x^(p/q)=log(y)
(p/q)*log(x)=logy
antilog((p/q)*log(x))=y
I think you want to create a program for this because such values can easily be calculated using scientific calculator
Am i right?
Last edited by goyal420; 23rd December 2009 at 05:36 PM.
Opportunities are like buses ,if one missed then another will come
visit my blog:- http://goyal1989.blogspot.com Mail me :- goyal@crazyengineers.net






You can directly calculate provided the powers are in calculatable range.
If not you can follow the logarithms and log tables.
where you will be able to get the details.
scientific calculator can be used , you can get the values easily.

i want the result without using logarithm!






You can also calculate it manually
you can write
x^(p/q)=(x^(1/q))^p
say you want to calculate
27^(2/3)
then you can get the result.,by writing like this
(27^(1/3))^2)
Now i hope you know how to calculate
27^(1/3)
Opportunities are like buses ,if one missed then another will come
visit my blog:- http://goyal1989.blogspot.com Mail me :- goyal@crazyengineers.net

Thanks for all CEans they try to help me, i got an idea with Newton Raphson method, and now i am able to do!