Puzzlefor you all!!!!

[devesh]

So here comes a new puzzle for everyone....
you have to use the mathematical operators in between the numbers to get the correct output....

1 1 1 =6
2 2 2 =6
3 3 3 =6
4 4 4 =6
5 5 5 =6
6 6 6 =6
7 7 7 =6
8 8 8 =6
9 9 9 =6

its very simple ,you all can easily solve it....

[The_Big_K]

(1+1+1)! = 6
2+2+2 = 6
3x3-3 = 6
4+4-(sqrt 4) = 6 [positive square root]
(5/5)+5 = 6
6-6+6 = 6
7-(7/7) = 6

- bah -

(squrt 9) x (sqrt 9) - (sqrt 9) =6

[mahul]

I hope to answer the 8,

8-sqrt(8/(cube root(8))) = 6

[The_Big_K]

Originally Posted by mahul

I hope to answer the 8,

8-sqrt(8/(cube root(8))) = 6

If I were not bored, I'd do -

cuberoot (8) + cuberoot (8) + cuberoot (8) = 6

[mahul]

Wow! that's a lot better....

[devesh]

wow...
such quick replies..
CE rocks!!!!

[Ayan]

Originally Posted by The_Big_K

(1+1+1)! = 6
2+2+2 = 6
3x3-3 = 6
4+4-(sqrt 4) = 6 [positive square root]
(5/5)+5 = 6
6-6+6 = 6
7-(7/7) = 6

- bah -

(squrt 9) x (sqrt 9) - (sqrt 9) =6

sorry again using for testing perpose

[Ayan]

Originally Posted by Ayan

sorry again using for testing perpose

jhkajshdkajsdasdasdasdasdasdasdadasdasdasdasd

[The_Big_K]

Ayan, take this as yet-another warning. Further spamming will lead to banning. If you want to make test posts, go here -

CE - Newbie Training Center - CrazyEngineers Forum

of course, instead of posting 'jdfsdlks...', try posting something that makes sense.