[Nidhinkoroth]

Compressed Air

Energy of the compressed air
Using Boyle law we get that
E = 10(xLx-x+1) where
E = Energy in Kilogrameters in a tank of one liter volume.
One kilogrameter is a force of one kilo in one meter, is the same energy of 9.81 Joules.
367000 Kilogrameters is a KWH
KWH = Kilowatt hour
Kgm = Kilogrameter
The absolute pressure in the tank is x Kg/cm the absolute pressure is the relative pressure plus one.

Example: The pressure in the gauge of the tank is 10 kg /cm absolute pressure of the tank is 10+1=11 kg/cm
E = 10(11L11-11+1) = 163.758 Kgm
L11 = 2.3978

Volume of the tanks 300 liters
Maximum pressure 352 Kg / cm
Volume of the air at atmosphere pressure 352 x 300 = 105600 liters
Energy for each liter at 352 Kg / cm = 17188 Kgm
Energy in the tanks 17188 x 300 = 5156400 Kgm
Energy in the tanks in KWH 5156400 / 367000 = 14.05 KWH
Efficiency of the compressor 60 %
Electricity for charge the tanks 5156400 / 60 x 100 = 8594000 Kgm
Electricity for charge the tanks in KWH 8594000 / 367000 = 23.4 KWH
Efficiency of the motor 60 %
Speed of the car 80 Km / h
Force for move the car 25 Kgf
Range 3093840 / 25000 = 123 Km
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